channel 源码解析(5问)

news2024/11/19 18:20:58

目录

1.channel底层数据结构是什么

2.channel创建的底层实现

3.channel 的发送过程

4.channel的接受过程

5.关闭 channel


1.channel底层数据结构是什么

channel底层的数据结构是hchan,包括一个循环链表和2个双向链表

type hchan struct {
	qcount   uint           // total data in the queue
	dataqsiz uint           // size of the circular queue
	buf      unsafe.Pointer // points to an array of dataqsiz elements
	elemsize uint16
	closed   uint32
	elemtype *_type // element type
	sendx    uint   // send index
	recvx    uint   // receive index
	recvq    waitq  // list of recv waiters
	sendq    waitq  // list of send waiters

	// lock protects all fields in hchan, as well as several
	// fields in sudogs blocked on this channel.
	//
	// Do not change another G's status while holding this lock
	// (in particular, do not ready a G), as this can deadlock
	// with stack shrinking.
	lock mutex
}
buf:循环链表

sendx:循环链表中已发送的位置

recvx: 循环链表中已接受的位置

qcount:环形队列的实际大小

dataqsiz:环形队列的容量

elemsize:环列队列中元素的大小

elemtype:环形队列中元素的类型

closed:环形队列是否关闭

recvq:等待接收groutinue链表

sendq:等待发送send groutinue链表

lock:悲观锁

结构图如下所示

2.channel创建的底层实现

创建channel底层调用的是makechan,为新创建的channel分配内存空间,分为下面的三种情况:

  1. 不带缓冲区:只需要给hchan分配内存空间。
  2. 带缓冲区且不包括指针类型:同时给hchan和环形队列缓存buf分配一段连续的内存空间
  3. 带缓冲区且包括指针类型:分别给hchan和环形队列缓存buf分配不同的内存空间。

源码如下:

func makechan64(t *chantype, size int64) *hchan {
	if int64(int(size)) != size {
		panic(plainError("makechan: size out of range"))
	}

	return makechan(t, int(size))
}

func makechan(t *chantype, size int) *hchan {
	elem := t.elem

	// compiler checks this but be safe.
	if elem.size >= 1<<16 {
		throw("makechan: invalid channel element type")
	}
	if hchanSize%maxAlign != 0 || elem.align > maxAlign {
		throw("makechan: bad alignment")
	}

	mem, overflow := math.MulUintptr(elem.size, uintptr(size))
	if overflow || mem > maxAlloc-hchanSize || size < 0 {
		panic(plainError("makechan: size out of range"))
	}

	// Hchan does not contain pointers interesting for GC when elements stored in buf do not contain pointers.
	// buf points into the same allocation, elemtype is persistent.
	// SudoG's are referenced from their owning thread so they can't be collected.
	// TODO(dvyukov,rlh): Rethink when collector can move allocated objects.
	var c *hchan
	switch {
	case mem == 0:
		// Queue or element size is zero.
		c = (*hchan)(mallocgc(hchanSize, nil, true))
		// Race detector uses this location for synchronization.
		c.buf = c.raceaddr()
	case elem.ptrdata == 0:
		// Elements do not contain pointers.
		// Allocate hchan and buf in one call.
		c = (*hchan)(mallocgc(hchanSize+mem, nil, true))
		c.buf = add(unsafe.Pointer(c), hchanSize)
	default:
		// Elements contain pointers.
		c = new(hchan)
		c.buf = mallocgc(mem, elem, true)
	}

	c.elemsize = uint16(elem.size)
	c.elemtype = elem
	c.dataqsiz = uint(size)
	lockInit(&c.lock, lockRankHchan)

	if debugChan {
		print("makechan: chan=", c, "; elemsize=", elem.size, "; dataqsiz=", size, "\n")
	}
	return c
}

3.channel 的发送过程

channel send 发送底层调用的是chansend1函数

channel发送的过程

1.检查 recvq 双向链表 是否为空,如果不为空,说明recvq缓存队列不为空,buffer为空,有大量的recvq在等待,则从 recvq 头部取一个 goroutine,将数据发送过去,并唤醒对应的 goroutine 即可。

2.如果 recvq 为空,代表buffer可能有存储空间,则将数据放入到 buffer 中。

3.如果 buffer 已满,则将要发送的数据和当前 goroutine 打包成 sudog 对象放入到 sendq 中。并将当前 goroutine 置为 waiting 状态。

源码如下

func chansend1(c *hchan, elem unsafe.Pointer) {
	chansend(c, elem, true, getcallerpc())
}

/*
 * generic single channel send/recv
 * If block is not nil,
 * then the protocol will not
 * sleep but return if it could
 * not complete.
 *
 * sleep can wake up with g.param == nil
 * when a channel involved in the sleep has
 * been closed.  it is easiest to loop and re-run
 * the operation; we'll see that it's now closed.
 */
func chansend(c *hchan, ep unsafe.Pointer, block bool, callerpc uintptr) bool {
	if c == nil {
		if !block {
			return false
		}
		gopark(nil, nil, waitReasonChanSendNilChan, traceEvGoStop, 2)
		throw("unreachable")
	}

	if debugChan {
		print("chansend: chan=", c, "\n")
	}

	if raceenabled {
		racereadpc(c.raceaddr(), callerpc, funcPC(chansend))
	}

	// Fast path: check for failed non-blocking operation without acquiring the lock.
	//
	// After observing that the channel is not closed, we observe that the channel is
	// not ready for sending. Each of these observations is a single word-sized read
	// (first c.closed and second full()).
	// Because a closed channel cannot transition from 'ready for sending' to
	// 'not ready for sending', even if the channel is closed between the two observations,
	// they imply a moment between the two when the channel was both not yet closed
	// and not ready for sending. We behave as if we observed the channel at that moment,
	// and report that the send cannot proceed.
	//
	// It is okay if the reads are reordered here: if we observe that the channel is not
	// ready for sending and then observe that it is not closed, that implies that the
	// channel wasn't closed during the first observation. However, nothing here
	// guarantees forward progress. We rely on the side effects of lock release in
	// chanrecv() and closechan() to update this thread's view of c.closed and full().
	if !block && c.closed == 0 && full(c) {
		return false
	}

	var t0 int64
	if blockprofilerate > 0 {
		t0 = cputicks()
	}

	lock(&c.lock)

	if c.closed != 0 {
		unlock(&c.lock)
		panic(plainError("send on closed channel"))
	}
    //recvq不为空
	if sg := c.recvq.dequeue(); sg != nil {
		// Found a waiting receiver. We pass the value we want to send
		// directly to the receiver, bypassing the channel buffer (if any).
		send(c, sg, ep, func() { unlock(&c.lock) }, 3)
		return true
	}

    //
	if c.qcount < c.dataqsiz {
		// Space is available in the channel buffer. Enqueue the element to send.
		qp := chanbuf(c, c.sendx)
		if raceenabled {
			racenotify(c, c.sendx, nil)
		}
		typedmemmove(c.elemtype, qp, ep)
		c.sendx++
		if c.sendx == c.dataqsiz {
			c.sendx = 0
		}
		c.qcount++
		unlock(&c.lock)
		return true
	}

	if !block {
		unlock(&c.lock)
		return false
	}

	// Block on the channel. Some receiver will complete our operation for us.
	gp := getg()
	mysg := acquireSudog()
	mysg.releasetime = 0
	if t0 != 0 {
		mysg.releasetime = -1
	}
	// No stack splits between assigning elem and enqueuing mysg
	// on gp.waiting where copystack can find it.
	mysg.elem = ep
	mysg.waitlink = nil
	mysg.g = gp
	mysg.isSelect = false
	mysg.c = c
	gp.waiting = mysg
	gp.param = nil
	c.sendq.enqueue(mysg)
	// Signal to anyone trying to shrink our stack that we're about
	// to park on a channel. The window between when this G's status
	// changes and when we set gp.activeStackChans is not safe for
	// stack shrinking.
	atomic.Store8(&gp.parkingOnChan, 1)
	gopark(chanparkcommit, unsafe.Pointer(&c.lock), waitReasonChanSend, traceEvGoBlockSend, 2)
	// Ensure the value being sent is kept alive until the
	// receiver copies it out. The sudog has a pointer to the
	// stack object, but sudogs aren't considered as roots of the
	// stack tracer.
	KeepAlive(ep)

	// someone woke us up.
	if mysg != gp.waiting {
		throw("G waiting list is corrupted")
	}
	gp.waiting = nil
	gp.activeStackChans = false
	closed := !mysg.success
	gp.param = nil
	if mysg.releasetime > 0 {
		blockevent(mysg.releasetime-t0, 2)
	}
	mysg.c = nil
	releaseSudog(mysg)
	if closed {
		if c.closed == 0 {
			throw("chansend: spurious wakeup")
		}
		panic(plainError("send on closed channel"))
	}
	return true
}

4.channel的接受过程

channel底层调用的是chanrecv、chanrecv1、chanrecv2,chanrecv1和chanrecv2底层都调用的是chanrecv。chanrecv1和chanrecv2区别有没有接受数据成功的bool类型

 chanrecv1(c *hchan, elem unsafe.Pointer)
 chanrecv2(c *hchan, elem unsafe.Pointer) (received bool)

receiver过程分为4种情况

1.从sendq队列头部取一个元素,如果元素不为空,环形队列缓存区已满,说明buffer已满,大量的send goroutine在发送数据,阻塞了,rece从循环队列读取一个元素,,把goroutinue元素放在循环队列中,从sendq队列中唤醒goroutinue。

2.从sendq队列头部取一个元素,如果元素不为空,环形队列为空,并把goroutine中元素copy到receiver中,从sendq队列中唤醒一个goroutine,

3.sendq队列为空,buffer没有满,从buffer中获取一个元素,recex+1

4.sendq对列为空,buffer为空,rece的goroutinue包装成sudog,放在receq队列中。

channel recv的底层源码如下

// entry points for <- c from compiled code
//go:nosplit
func chanrecv1(c *hchan, elem unsafe.Pointer) {
	chanrecv(c, elem, true)
}

//go:nosplit
func chanrecv2(c *hchan, elem unsafe.Pointer) (received bool) {
	_, received = chanrecv(c, elem, true)
	return
}

// chanrecv receives on channel c and writes the received data to ep.
// ep may be nil, in which case received data is ignored.
// If block == false and no elements are available, returns (false, false).
// Otherwise, if c is closed, zeros *ep and returns (true, false).
// Otherwise, fills in *ep with an element and returns (true, true).
// A non-nil ep must point to the heap or the caller's stack.
func chanrecv(c *hchan, ep unsafe.Pointer, block bool) (selected, received bool) {
	// raceenabled: don't need to check ep, as it is always on the stack
	// or is new memory allocated by reflect.

	if debugChan {
		print("chanrecv: chan=", c, "\n")
	}

	if c == nil {
		if !block {
			return
		}
		gopark(nil, nil, waitReasonChanReceiveNilChan, traceEvGoStop, 2)
		throw("unreachable")
	}

	// Fast path: check for failed non-blocking operation without acquiring the lock.
	if !block && empty(c) {
		// After observing that the channel is not ready for receiving, we observe whether the
		// channel is closed.
		//
		// Reordering of these checks could lead to incorrect behavior when racing with a close.
		// For example, if the channel was open and not empty, was closed, and then drained,
		// reordered reads could incorrectly indicate "open and empty". To prevent reordering,
		// we use atomic loads for both checks, and rely on emptying and closing to happen in
		// separate critical sections under the same lock.  This assumption fails when closing
		// an unbuffered channel with a blocked send, but that is an error condition anyway.
		if atomic.Load(&c.closed) == 0 {
			// Because a channel cannot be reopened, the later observation of the channel
			// being not closed implies that it was also not closed at the moment of the
			// first observation. We behave as if we observed the channel at that moment
			// and report that the receive cannot proceed.
			return
		}
		// The channel is irreversibly closed. Re-check whether the channel has any pending data
		// to receive, which could have arrived between the empty and closed checks above.
		// Sequential consistency is also required here, when racing with such a send.
		if empty(c) {
			// The channel is irreversibly closed and empty.
			if raceenabled {
				raceacquire(c.raceaddr())
			}
			if ep != nil {
				typedmemclr(c.elemtype, ep)
			}
			return true, false
		}
	}

	var t0 int64
	if blockprofilerate > 0 {
		t0 = cputicks()
	}

	lock(&c.lock)

	if c.closed != 0 && c.qcount == 0 {
		if raceenabled {
			raceacquire(c.raceaddr())
		}
		unlock(&c.lock)
		if ep != nil {
			typedmemclr(c.elemtype, ep)
		}
		return true, false
	}

	if sg := c.sendq.dequeue(); sg != nil {
		// Found a waiting sender. If buffer is size 0, receive value
		// directly from sender. Otherwise, receive from head of queue
		// and add sender's value to the tail of the queue (both map to
		// the same buffer slot because the queue is full).
		recv(c, sg, ep, func() { unlock(&c.lock) }, 3)
		return true, true
	}

	if c.qcount > 0 {
		// Receive directly from queue
		qp := chanbuf(c, c.recvx)
		if raceenabled {
			racenotify(c, c.recvx, nil)
		}
		if ep != nil {
			typedmemmove(c.elemtype, ep, qp)
		}
		typedmemclr(c.elemtype, qp)
		c.recvx++
		if c.recvx == c.dataqsiz {
			c.recvx = 0
		}
		c.qcount--
		unlock(&c.lock)
		return true, true
	}

	if !block {
		unlock(&c.lock)
		return false, false
	}

	// no sender available: block on this channel.
	gp := getg()
	mysg := acquireSudog()
	mysg.releasetime = 0
	if t0 != 0 {
		mysg.releasetime = -1
	}
	// No stack splits between assigning elem and enqueuing mysg
	// on gp.waiting where copystack can find it.
	mysg.elem = ep
	mysg.waitlink = nil
	gp.waiting = mysg
	mysg.g = gp
	mysg.isSelect = false
	mysg.c = c
	gp.param = nil
	c.recvq.enqueue(mysg)
	// Signal to anyone trying to shrink our stack that we're about
	// to park on a channel. The window between when this G's status
	// changes and when we set gp.activeStackChans is not safe for
	// stack shrinking.
	atomic.Store8(&gp.parkingOnChan, 1)
	gopark(chanparkcommit, unsafe.Pointer(&c.lock), waitReasonChanReceive, traceEvGoBlockRecv, 2)

	// someone woke us up
	if mysg != gp.waiting {
		throw("G waiting list is corrupted")
	}
	gp.waiting = nil
	gp.activeStackChans = false
	if mysg.releasetime > 0 {
		blockevent(mysg.releasetime-t0, 2)
	}
	success := mysg.success
	gp.param = nil
	mysg.c = nil
	releaseSudog(mysg)
	return true, success
}

5.关闭 channel

关闭channel底层源码调用的是closechan

除此之外,关闭channel,出现panic的场景如下:

  1. 关闭值为nil的channel
  2. 关闭已经被关闭的channel
  3. 向已经关闭的channel写数据

关闭channel的源码如下

func closechan(c *hchan) {
	if c == nil {
		panic(plainError("close of nil channel"))
	}

	lock(&c.lock)
	if c.closed != 0 {
		unlock(&c.lock)
		panic(plainError("close of closed channel"))
	}

	if raceenabled {
		callerpc := getcallerpc()
		racewritepc(c.raceaddr(), callerpc, funcPC(closechan))
		racerelease(c.raceaddr())
	}

	c.closed = 1

	var glist gList

	// release all readers
	for {
		sg := c.recvq.dequeue()
		if sg == nil {
			break
		}
		if sg.elem != nil {
			typedmemclr(c.elemtype, sg.elem)
			sg.elem = nil
		}
		if sg.releasetime != 0 {
			sg.releasetime = cputicks()
		}
		gp := sg.g
		gp.param = unsafe.Pointer(sg)
		sg.success = false
		if raceenabled {
			raceacquireg(gp, c.raceaddr())
		}
		glist.push(gp)
	}

	// release all writers (they will panic)
	for {
		sg := c.sendq.dequeue()
		if sg == nil {
			break
		}
		sg.elem = nil
		if sg.releasetime != 0 {
			sg.releasetime = cputicks()
		}
		gp := sg.g
		gp.param = unsafe.Pointer(sg)
		sg.success = false
		if raceenabled {
			raceacquireg(gp, c.raceaddr())
		}
		glist.push(gp)
	}
	unlock(&c.lock)

	// Ready all Gs now that we've dropped the channel lock.
	for !glist.empty() {
		gp := glist.pop()
		gp.schedlink = 0
		goready(gp, 3)
	}
}

本文来自互联网用户投稿,该文观点仅代表作者本人,不代表本站立场。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如若转载,请注明出处:http://www.coloradmin.cn/o/418931.html

如若内容造成侵权/违法违规/事实不符,请联系多彩编程网进行投诉反馈,一经查实,立即删除!

相关文章

Linux命令·route

Linux系统的route命令用于显示和操作IP路由表&#xff08;show / manipulate the IP routing table&#xff09;。要实现两个不同的子网之间的通信&#xff0c;需要一台连接两个网络的路由器&#xff0c;或者同时位于两个网络的网关来实现。在Linux系统中&#xff0c;设置路由通…

BGP小型实验

实验分析 1.主要考察的是对BGP配置的熟练 2.实验需要在R1与R5分别发布一条路由可以在BGP 中使用network 网段 掩码命令 3.R1与R2,R4与R5是EBGP&#xff0c;而R2,R3,R4是IBGP 实验操作 1.配置接口ip,与环回路由 以R1为例 2.AS内部需要实现非直连的建立是需要保证IBGP内部是通的所…

网络编程之IP协议

&#x1f389;&#x1f389;&#x1f389;点进来你就是我的人了 博主主页&#xff1a;&#x1f648;&#x1f648;&#x1f648;戳一戳,欢迎大佬指点!人生格言&#xff1a;当你的才华撑不起你的野心的时候,你就应该静下心来学习! 欢迎志同道合的朋友一起加油喔&#x1f9be;&am…

ChatGPT 存在很大的隐私问题

当 OpenAI 发布时 2020 年 7 月的 GPT-3&#xff0c;它提供了用于训练大型语言模型的数据的一瞥。 根据一篇技术论文&#xff0c;从网络、帖子、书籍等中收集的数百万页被用于创建生成文本系统。 在此数据中收集的是您在网上分享的一些关于您自己的个人信息,这些数据现在让 O…

YGG 代表 Web3 Gaming 参加 2023 年游戏开发者大会

Yield Guild Games&#xff08;YGG&#xff09;在 2023 年 3 月 20 日至 24 日在加州旧金山举行的游戏开发者大会&#xff08;GDC&#xff09;上大显身手&#xff0c;这是游戏开发者的重要交流学习活动。虽然 GDC 本身提供了多种多样的活动&#xff0c;包括讲座、小组讨论、圆桌…

基于html+css的盒子展示6

准备项目 项目开发工具 Visual Studio Code 1.44.2 版本: 1.44.2 提交: ff915844119ce9485abfe8aa9076ec76b5300ddd 日期: 2020-04-16T16:36:23.138Z Electron: 7.1.11 Chrome: 78.0.3904.130 Node.js: 12.8.1 V8: 7.8.279.23-electron.0 OS: Windows_NT x64 10.0.19044 项目…

无公网IP?教你在外远程访问本地wamp服务器「内网穿透」

目录 前言 1.Wamp服务器搭建 1.1 Wamp下载和安装 1.2 Wamp网页测试 2. Cpolar内网穿透的安装和注册 2.1 本地网页发布 2.2 Cpolar云端设置 2.3 Cpolar本地设置 3. 公网访问测试 4. 结语 前言 软件技术的发展日新月异&#xff0c;各种能方便我们生活、工作和娱乐的新…

OA系统的功能和作用是什么(OA系统百科)

OA系统的功能和作用是什么&#xff08;OA系统百科&#xff09;。OA系统是一种非常实用的企业内部管理系统&#xff0c;它可以帮助公司实现各项管理工作&#xff0c;可以说是整个公司和团队的纽带&#xff0c;有助于提高工作效率和管理水平。 具体来说&#xff0c;OA系统的作用…

Linux运维进阶之路

前言 首先在我看来&#xff0c;不论你以后是做运维亦或者是做后端开发&#xff0c;云计算等。只要和后端搭边&#xff0c;Linux都是必会的基础知识。所以说Linux是伴随我们工作中一个特别重要的知识。 不过很多同学在初学Linux的时候&#xff0c;始终不得其法&#xff0c;发现…

科技赋能文旅:蓝海创意云携手苏州乐园打造“元宇宙灯会”

4月8日&#xff0c;苏州乐园“欢乐寻梦季”元宇宙灯会即将正式亮灯&#xff0c;这是一场以元宇宙技术为核心&#xff0c;结合现代灯展、数字科技、潮玩游乐等元素&#xff0c;打造的一场大型的沉浸式数字光影体验。 蓝海创意云作为苏州高新区元宇宙龙头企业&#xff0c;以多年…

量化择时——SVM机器学习量化择时(第1部分—因子测算)

文章目录机器学习在量化模型上的应用机器学习量化应用场景量化模型有效性的思考机器学习模型在量化择时中的应用训练与预测流程训练数据特征构造SVM模型与测算SVM训练与预测效果测算效果分析最近ChatGPT比较火&#xff0c;NLP的同学们感触肯定会更深。NLP的应用为人所知并积极部…

【电子学会】2022年12月图形化一级 -- 潜水

潜水 暑假小雨和爸爸去玩了潜水,他见到了各种各样的海洋生物。 1. 准备工作 (1)添加背景“Underwater 2”; (2)删除小猫角色,添加角色“Diver2”、“Fish”、“Jellyfish”、“Shark”; (3)为背景添加声音“Xylo2”。 2. 功能实现 (1)点击绿旗,播放背景音乐…

【chatGPT】chatGPT初步体验,赶快来学习吧

目录 1、什么是ChatGPT 2、我可以相信人工智能告诉我真相吗&#xff1f; 3、你会使用我的对话进行培训吗&#xff1f; 4、ChatGPT 接口参考 认证 请求组织 5、ChatGPT初体验 1、什么是ChatGPT ChatGPT的研究预览是免费使用的。 ChatGPT 是从 GPT-3.5 微调而来的&#x…

vue3+typescript+vant页面开发案例

文章目录效果index.vue页面template内容script内容index.ts页面效果 index.vue页面 template内容 <van-form submit"onSubmit"><van-cell-group inset><van-fieldv-model"providerApply.companyName"name"企业名称"label"企…

snipaste 截图工具——可以使图片悬浮在任何软件上,方便对比

一、下载 官网下载地址&#xff1a;Snipaste Downloads &#xff08;需要梯子&#xff09; CSDN下载地址&#xff1a;https://download.csdn.net/download/weixin_43042683/87671809 1. 下载 压缩包后&#xff0c;免安装&#xff0c;直接解压后既可以使用。 2. 点击Snipaste.…

【c语言】二维数组与指针 存储原理

创作不易&#xff0c;本篇文章如果帮助到了你&#xff0c;还请点赞支持一下♡>&#x16966;<)!! 主页专栏有更多知识&#xff0c;如有疑问欢迎大家指正讨论&#xff0c;共同进步&#xff01; 给大家跳段街舞感谢支持&#xff01;ጿ ኈ ቼ ዽ ጿ ኈ ቼ ዽ ጿ ኈ ቼ ዽ ጿ…

Adaptive Weight Assignment Scheme For Multi-task Learning

Adaptive Weight Assignment Scheme For Multi-task Learning 题目Adaptive Weight Assignment Scheme For Multi-task Learning译题用于多任务学习的自适应权重分配方案时间2022年期刊/会议IAES International Journal of Artificial Intelligence (IJ-AI) 摘要&#xff1a;如…

UDS 14229-1标准加Trace ,两万字长文详细解读

&#x1f345; 我是蚂蚁小兵&#xff0c;专注于车载诊断领域&#xff0c;尤其擅长于对CANoe工具的使用&#x1f345; 寻找组织 &#xff0c;答疑解惑&#xff0c;摸鱼聊天&#xff0c;博客源码&#xff0c;点击加入&#x1f449;【相亲相爱一家人】&#x1f345; 玩转CANoe&…

比较系统的学习 pandas(5)

pandas 常见的高级操作 1、进行复杂查询 由于不好描述&#xff0c;就举几个栗子吧&#xff0c;不明白的可以私聊我 1、pnadas 支持逻辑计算与位运算 对DataFrame的一列进行逻辑计&#xff0c;会产生一个对应的由布尔值组成的Series&#xff0c;真假值由此位上的数据 是否满…

ArrayList的深入理解

ArrayList的源码解析1. 实例化无参构造器2. add&#xff08;&#xff09;方法2.1. add&#xff08;&#xff09;List的扩容3. get&#xff08;&#xff09;方法4. remove&#xff08;&#xff09;5. modCount 的作用(面试题)5. 手写简单List实现存储删除1. 实例化无参构造器 A…