简单的事件循环，一道异步代码执行输出顺序问题?

第一题

        setTimeout(() => {
            console.log("A")
            Promise.resolve().then(() => { console.log("B"); });
        }, 1000);

        Promise.resolve().then(() => { console.log("c"); });

        new Promise((resolve) => {
            console.log("D");
            resolve("");
        }).then(() => {
            console.log("E");
        });
        async function sum(a, b) {  console.log("F")};

        async function asyncSum(a, b) {
                await Promise.resolve(); 
                console.log("G");
                return Promise.resolve(a + b);
        }
        
        sum(3, 4); 
        asyncSum(3, 4);
        console.log("H");

第二题

setTimeout(()=>console.log("A"));
Promise.resolve().then(()=> console.log("B"))
console. log("c");

答案我放在下面了↓ ↓ ↓ ↓ ↓ 看看你的答案对了没