198. 打家劫舍 - 力扣（LeetCode）

class Solution {
    public int rob(int[] nums) {
        int[] dp = new int[nums.length];

        if(nums.length == 1){
            return nums[0];
        }

        dp[0] = nums[0];
        dp[1] = Math.max(nums[0],nums[1]);

        for(int i=2;i<nums.length;i++){
            dp[i] = Math.max(dp[i-1],dp[i-2]+nums[i]);
        }

        return dp[nums.length-1];
    }
}

213. 打家劫舍 II - 力扣（LeetCode）

class Solution {
    public int rob(int[] nums) {
        if(nums.length == 1){
            return nums[0];
        }

        if(nums.length == 2){
            return Math.max(nums[0],nums[1]);
        }

        return Math.max(rob(nums,0,nums.length-2),rob(nums,1,nums.length-1));
    }

    public int rob(int[] nums,int beginIndex,int endIndex) {
        int[] dp = new int[endIndex-beginIndex+1];

        if(dp.length == 1){
            return nums[beginIndex];
        }

        dp[0] = nums[beginIndex];
        dp[1] = Math.max(nums[beginIndex],nums[beginIndex+1]);

        for(int i=beginIndex+2;i<=endIndex;i++){
            dp[i-beginIndex] = Math.max(dp[i-beginIndex-1],dp[i-beginIndex-2]+nums[i]);
        }

        return dp[dp.length-1];
    }
}

337. 打家劫舍 III - 力扣（LeetCode）

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public int rob(TreeNode root) {
        int[] curResult = doRob(root);
        
        return Math.max(curResult[0],curResult[1]);
        
    }
    
    public int[] doRob(TreeNode root){
        if(root == null){
            return new int[]{0,0};
        }
        
        if(root.left == null && root.right == null){
            return new int[]{0,root.val};
        }
        
        //左子树的值
        int[] left = doRob(root.left);
        //右子树的值
        int[] right = doRob(root.right);
        
        int notSelectCur = Math.max(left[0],left[1]) + Math.max(right[0],right[1]);
        int selectCur = root.val + left[0] + right[0];
        
        return new int[]{notSelectCur,selectCur};
    }
}