【设计模式】JAVA Design Patterns——Curiously Recurring Template Pattern（奇异递归模板模式）

news2024/11/25 23:18:24

🔍目的

允许派生组件从与派生类型兼容的基本组件继承某些功能。

🔍解释

真实世界例子

对于正在策划赛事的综合格斗推广活动来说，确保在相同重量级的运动员之间组织比赛至关重要。这样可以防止体型明显不同的拳手之间的不匹配，例如重量级拳手与雏量级拳手的对决。

通俗描述

使类型中的某些方法接受特定于其子类型的参数。

维基百科

奇异递归模板模式（curiously recurring template pattern，CRTP）是C++模板编程时的一种惯用法：其中类X派生自使用X本身作为模板参数的类模板实例化。

程序实例

定义一个通用接口Fighter

public interface Fighter<T> {

  void fight(T t);

}

定义MmaFighter类用于实例化按重量级别区分的拳手

public class MmaFighter<T extends MmaFighter<T>> implements Fighter<T> {

  private final String name;
  private final String surname;
  private final String nickName;
  private final String speciality;

  public MmaFighter(String name, String surname, String nickName, String speciality) {
    this.name = name;
    this.surname = surname;
    this.nickName = nickName;
    this.speciality = speciality;
  }

  @Override
  public void fight(T opponent) {
    LOGGER.info("{} is going to fight against {}", this, opponent);
  }

  @Override
  public String toString() {
    return name + " \"" + nickName + "\" " + surname;
  }

定义MmaFighter 的一些子类型

class MmaBantamweightFighter extends MmaFighter<MmaBantamweightFighter> {

  public MmaBantamweightFighter(String name, String surname, String nickName, String speciality) {
    super(name, surname, nickName, speciality);
  }

}

public class MmaHeavyweightFighter extends MmaFighter<MmaHeavyweightFighter> {

  public MmaHeavyweightFighter(String name, String surname, String nickName, String speciality) {
    super(name, surname, nickName, speciality);
  }

}

效果：允许拳手与相同重量级的对手交手，如果对手是不同重量级，则会出现错误

MmaBantamweightFighter fighter1 = new MmaBantamweightFighter("Joe", "Johnson", "The Geek", "Muay Thai");
MmaBantamweightFighter fighter2 = new MmaBantamweightFighter("Ed", "Edwards", "The Problem Solver", "Judo");
fighter1.fight(fighter2); // This is fine

MmaHeavyweightFighter fighter3 = new MmaHeavyweightFighter("Dave", "Davidson", "The Bug Smasher", "Kickboxing");
MmaHeavyweightFighter fighter4 = new MmaHeavyweightFighter("Jack", "Jackson", "The Pragmatic", "Brazilian Jiu-Jitsu");
fighter3.fight(fighter4); // This is fine too

fighter1.fight(fighter3); // This will raise a compilation error