Leetcode—289. 生命游戏【中等】

news2024/11/27 6:29:31

2024每日刷题（126）

Leetcode—289. 生命游戏

在这里插入图片描述

算法思想

在这里插入图片描述

实现代码

class Solution {
public:
    void gameOfLife(vector<vector<int>>& board) {
        int rows = board.size();
        int cols = board[0].size();
        int neighbors[3] = {0, 1, -1};

        vector<vector<int>> copyBoard(rows, vector<int>(cols, 0));
        for(int i = 0; i < rows; i++) {
            for(int j = 0; j < cols; j++) {
                copyBoard[i][j] = board[i][j];
            }
        }

        int r, c;
        for(int i = 0; i < rows; i++) {
            for(int j = 0; j < cols; j++) {
                int liveNum = 0;
                for(int row = 0; row < 3; row++) {
                    for(int col = 0; col < 3; col++) {
                        if(!(neighbors[row] == 0 && neighbors[col] == 0)) {
                            r = i + neighbors[row];
                            c = j + neighbors[col];
                            if((r >= 0 && r < rows) && (c >= 0 && c < cols) &&(copyBoard[r][c] == 1)) {
                                liveNum++;
                            }
                        }
                    }
                }

                // 条件1、3
                if((board[i][j] == 1) && (liveNum < 2 || liveNum > 3)) {
                    board[i][j] = 0;
                }
                // 条件4
                if(board[i][j] == 0 && liveNum == 3) {
                    board[i][j] = 1;
                }
            }
        }
    }
};