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思路： 

此题只需要两层循环，通过数组映射即可求出答案

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AC代码：

#include<iostream>

using namespace std;

typedef long long ll;
const int N = 10;
int a[N];

int main()
{
	ll n,m;
	cin >> n >> m;
	for(ll i=n;i<=m;i++)
	{
		ll num = i;
		while(num != 0)
		{
			ll c = num % 10;
			a[c] ++;
			num /= 10;
		}
	}
	for(int i=0;i<N;i++) cout << a[i] << ' ';
	return 0;
}