题目描述

给定一个整数 num，将其转化为 7 进制，并以字符串形式输出。

问题分析

按照二进制转换的方式进行转换即可

代码

char* convertToBase7(int num) {
    int count = 0;
    char *x = (char *)malloc(sizeof(char)*32);
    char *y = (char *)malloc(sizeof(char)*32);
    if(num>0){
        while(num!=0){
            x[count] = num%7+'0';
            num/=7;
            count=count+1;        
        }
        x[count] = 0;
        for(int i=0; i<count; i++){
            y[i] = x[count-1-i];
        }
        y[count] = 0;
    }else if(num==0){
        x[0] = '0';
        x[1] = 0;
        return x;
    }else{
        num = -1*num;
        while(num!=0){
            x[count] = num%7+'0';
            num/=7;  
            count++;      
        }
        for(int i=0; i<count; i++){
            y[i+1] = x[count-1-i];
        }
        y[0] = '-';
        y[count+1] = 0;
    }
    return y;
}

提交结果截图