请编写一段单词统计Python代码，统计下面两个Python三引号字符串里英文单词的词频。要求：

• 单词请忽略大小写
  使用数组splits = ['\n', ' ', '-', ':', '/', '*', '_', '(', ')', '"', '”', '“',']','[']来切割单词
  输出词频最高的5个单词和词频信息

'''
* Python 代码风格指南',
    * [google-python-styleguide_zh_cn](https://zh-google-styleguide.readthedocs.io/en/latest/google-python-styleguide/python_style_rules /)
    * [PEP8](https://legacy.python.org/dev/peps/pep-0008/)
* 代码风格和自动完成工具链
    * 基本工具
        * [pylint](https://pylint.org/)
        * [autopep8](https://pypi.org/project/autopep8/)
    * Visual Studio Code Python 开发基本插件
        * Pylance
        * Python Path
        * Python-autopep8
'''

 '''
Every major open-source project has its own style guide: a set of conventions (sometimes arbitrary) about how to write code for that project. It is much easier to understand a large codebase when all the code in it is in a consistent style.

“Style” covers a lot of ground, from “use camelCase for variable names” to “never use global variables” to “never use exceptions.” This project (google/styleguide) links to the style guidelines we use for Google code. If you are modifying a project that originated at Google, you may be pointed to this page to see the style guides that apply to that project.

This project holds the C++ Style Guide, C# Style Guide, Swift Style Guide, Objective-C Style Guide, Java Style Guide, Python Style Guide, R Style Guide, Shell Style Guide, HTML/CSS Style Guide, JavaScript Style Guide, TypeScript Style Guide, AngularJS Style Guide, Common Lisp Style Guide, and Vimscript Style Guide. This project also contains cpplint, a tool to assist with style guide compliance, and google-c-style.el, an Emacs settings file for Google style.
'''

预期结果：

def top_words(splits, text, top_n=5):
    i = 0
    word_dict = {}
    chars = []
    while i < len(text):
        c = text[i]
        if c in splits:
            # 过滤掉分隔字符串
            while i+1 < len(text) and text[i+1] in splits:
                i += 1
            word = ''.join(chars).lower()

            # 统计词频
            # TODO(You): 请在此添加代码
            word_info = word_dict.get(word)
            if word_info is None:
                word_info = {'word': word, 'count': 1}
                word_dict[word] = word_info
            else:
                word_info['count'] += 1
            chars = []
        else:
            chars.append(c)
                                     
        i += 1

    word_list = list(word_dict.values())
    top_n = min(top_n, len(word_list))
    word_list.sort(key=lambda word_info: word_info['count'], reverse=True)
    return word_list[0:top_n]

if __name__ == '__main__':
    google_style_guide = ...
    python_style_guides = ...
    splits = [' ', '-', ':', '/', '*', '_', '(', ')', '"', '”', '“']

    tops = top_words(splits, google_style_guide+python_style_guides)

    print('单词排行榜')
    print('--------')
    i = 0
    while i < len(tops):
        top = tops[i]
        word = top['word']
        count = top['count']
        print(f'{i+1}. 单词：{word}, 词频：{count}')
        i += 1

word_info = word_dict.get(word, {'word': word, 'count': 0})
word_info['count'] += 1
word_dict[word] = word_info

代码理解：

word_dict[word]是以word查找下标

word_info['count']是以count查找下标

类似于key和value里面的key值

word_info输出形式是

 如下代码中的赋值看不懂

word_info = word_dict.get(word[1], {"word": word[1], "count": 0})

1. get()方法里面如果word_dict中不包含word会怎么执行？word_info的值为空吗？

 如果键不在字典中，想要自己设置返回值

如果键不在字典中，想要自己设置返回值，可以这样处理，例如dict.get(‘键’,‘never’)，键在字典中，则返回键对应的值，键不在字典中，则返回never。

dict1={'国家':'中国','首都':'北京'}
print(dict1.get('国家'))
print(dict1.get('首都','never'))
print(dict1.get('省会','never'))
原文链接：https://blog.csdn.net/weixin_42709563/article/details/106593628

所以

word = 'test'
word_dict = {}
word_info = word_dict.get(word, {"word": word, "count": 0})

由于word的值（='test'）不在word_dict（为空）字典里，所以get(word,{"word":word,"count":0}的含义是如果不在，直接返回word_info: {'word': 'test', 'count': 0}